The problem asks to evaluate the expression $\frac{\frac{1}{3} \times \frac{1}{5} \div \frac{2}{3} \times \frac{1}{4}}{\frac{1}{4} \div \frac{1}{2}}$.

ArithmeticFractionsOrder of OperationsFraction MultiplicationFraction Division
2025/4/22

1. Problem Description

The problem asks to evaluate the expression 13×15÷23×1414÷12\frac{\frac{1}{3} \times \frac{1}{5} \div \frac{2}{3} \times \frac{1}{4}}{\frac{1}{4} \div \frac{1}{2}}.

2. Solution Steps

First, let's simplify the numerator:
13×15÷23×14\frac{1}{3} \times \frac{1}{5} \div \frac{2}{3} \times \frac{1}{4}
Multiplication and division are performed from left to right.
13×15=115\frac{1}{3} \times \frac{1}{5} = \frac{1}{15}
So, 115÷23×14\frac{1}{15} \div \frac{2}{3} \times \frac{1}{4}.
To divide fractions, we multiply by the reciprocal.
115÷23=115×32=330=110\frac{1}{15} \div \frac{2}{3} = \frac{1}{15} \times \frac{3}{2} = \frac{3}{30} = \frac{1}{10}.
Now, 110×14=140\frac{1}{10} \times \frac{1}{4} = \frac{1}{40}.
The numerator simplifies to 140\frac{1}{40}.
Next, let's simplify the denominator:
14÷12\frac{1}{4} \div \frac{1}{2}
To divide fractions, we multiply by the reciprocal.
14÷12=14×21=24=12\frac{1}{4} \div \frac{1}{2} = \frac{1}{4} \times \frac{2}{1} = \frac{2}{4} = \frac{1}{2}.
So, the expression becomes 14012\frac{\frac{1}{40}}{\frac{1}{2}}.
To divide fractions, we multiply by the reciprocal.
140÷12=140×21=240=120\frac{1}{40} \div \frac{1}{2} = \frac{1}{40} \times \frac{2}{1} = \frac{2}{40} = \frac{1}{20}.

3. Final Answer

The final answer is 120\frac{1}{20}

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