The problem is to evaluate the expression $(\frac{7}{9} \div \frac{14}{21}) \times (\frac{3}{5} \div \frac{1}{4})$.

ArithmeticFractionsArithmetic OperationsOrder of Operations
2025/4/22

1. Problem Description

The problem is to evaluate the expression (79÷1421)×(35÷14)(\frac{7}{9} \div \frac{14}{21}) \times (\frac{3}{5} \div \frac{1}{4}).

2. Solution Steps

First, we simplify the expression inside the first parenthesis. Dividing by a fraction is the same as multiplying by its reciprocal. So,
79÷1421=79×2114\frac{7}{9} \div \frac{14}{21} = \frac{7}{9} \times \frac{21}{14}.
Simplify the fraction before multiplication:
79×2114=79×3×72×7=19×3×72=13×3×3×72=13×72=76\frac{7}{9} \times \frac{21}{14} = \frac{7}{9} \times \frac{3 \times 7}{2 \times 7} = \frac{1}{9} \times \frac{3 \times 7}{2} = \frac{1}{3 \times 3} \times \frac{3 \times 7}{2} = \frac{1}{3} \times \frac{7}{2} = \frac{7}{6}.
Next, we simplify the expression inside the second parenthesis. Dividing by a fraction is the same as multiplying by its reciprocal. So,
35÷14=35×41=3×45×1=125\frac{3}{5} \div \frac{1}{4} = \frac{3}{5} \times \frac{4}{1} = \frac{3 \times 4}{5 \times 1} = \frac{12}{5}.
Now, we multiply the results from the parentheses:
76×125=76×2×65=71×25=7×21×5=145\frac{7}{6} \times \frac{12}{5} = \frac{7}{6} \times \frac{2 \times 6}{5} = \frac{7}{1} \times \frac{2}{5} = \frac{7 \times 2}{1 \times 5} = \frac{14}{5}.

3. Final Answer

The final answer is 145\frac{14}{5}.

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