The problem asks us to evaluate the expression $\frac{(2^2 \times 7)^2}{7^2}$.

ArithmeticExponentsOrder of OperationsSimplification
2025/4/22

1. Problem Description

The problem asks us to evaluate the expression (22×7)272\frac{(2^2 \times 7)^2}{7^2}.

2. Solution Steps

First, we simplify the expression inside the parenthesis:
22=42^2 = 4.
So, the expression inside the parenthesis is 4×7=284 \times 7 = 28.
Now we have:
(28)272\frac{(28)^2}{7^2}.
Next, we can rewrite the expression as:
28272=(287)2\frac{28^2}{7^2} = (\frac{28}{7})^2.
Since 28/7=428/7 = 4, we have:
(287)2=42=16(\frac{28}{7})^2 = 4^2 = 16.

3. Final Answer

16

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