The problem asks to find the value of the expression $(2^2 \times 7)^2 \div 7^2$.

1. Problem Description

The problem asks to find the value of the expression $(2^2 \times 7)^2 \div 7^2$.

2. Solution Steps

We are asked to evaluate $(2^2 \times 7)^2 \div 7^2$.

First, we evaluate $2^2$:

$2^2 = 2 \times 2 = 4$.

Now we have $(4 \times 7)^2 \div 7^2$.

Next, we evaluate $4 \times 7$:

$4 \times 7 = 28$.

Now we have $(28)^2 \div 7^2$.

Next, we evaluate $28^2$ and $7^2$:

$28^2 = 28 \times 28 = 784$.

$7^2 = 7 \times 7 = 49$.

Now we have $784 \div 49$.

Finally, we divide 784 by 49:

$784 \div 49 = 16$.

Alternatively, we can use the property $(ab)^n = a^n b^n$ and $(a/b)^n = a^n/b^n$.

$(2^2 \times 7)^2 \div 7^2 = (2^2)^2 \times 7^2 \div 7^2 = 2^{2 \times 2} \times 7^2 \div 7^2 = 2^4 \times 7^2 \div 7^2$.

Since $7^2 \div 7^2 = 1$, we have $2^4 \times 1 = 2^4$.

$2^4 = 2 \times 2 \times 2 \times 2 = 16$.

3. Final Answer

16