The problem states that a line $l$ has a slope $m = -\frac{2}{3}$. We are asked to find the slope of a line that is perpendicular to $l$.

GeometryLinesSlopePerpendicular Lines
2025/4/22

1. Problem Description

The problem states that a line ll has a slope m=23m = -\frac{2}{3}. We are asked to find the slope of a line that is perpendicular to ll.

2. Solution Steps

If two lines are perpendicular, the product of their slopes is 1-1.
Let m1m_1 be the slope of line ll and m2m_2 be the slope of a line perpendicular to ll.
Then m1m2=1m_1 \cdot m_2 = -1.
We are given that m1=23m_1 = -\frac{2}{3}. So,
23m2=1-\frac{2}{3} \cdot m_2 = -1
m2=1(32)m_2 = -1 \cdot (-\frac{3}{2})
m2=32m_2 = \frac{3}{2}

3. Final Answer

The slope of a line perpendicular to ll is 32\frac{3}{2}. The answer is b).

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