The problem is a worksheet about exponents. It includes writing numbers in exponential form, expanded form, and standard form. It also asks to identify the base of a number and solve some related problems.

ArithmeticExponentsExponential FormExpanded FormStandard FormBase
2025/4/24

1. Problem Description

The problem is a worksheet about exponents. It includes writing numbers in exponential form, expanded form, and standard form. It also asks to identify the base of a number and solve some related problems.

2. Solution Steps

1. Write $5 \times 5 \times 5 \times 5 \times 5 \times 5$ in exponential form.

Since 5 is multiplied by itself 6 times, the exponential form is 565^6.

2. Write $7^4$ in expanded form.

747^4 means 7 multiplied by itself 4 times, so the expanded form is 7×7×7×77 \times 7 \times 7 \times 7.

3. Write each number below in standard form.

25=2×2×2×2×2=322^5 = 2 \times 2 \times 2 \times 2 \times 2 = 32
33=3×3×3=273^3 = 3 \times 3 \times 3 = 27
112=11×11=12111^2 = 11 \times 11 = 121
43=4×4×4=644^3 = 4 \times 4 \times 4 = 64

4. Write the base of each number.

The base of 878^7 is

8. The base of $7^9$ is

7. The base of $25^{10}$ is

2

5. The base of $12^4$ is

1
2.

5. If you write $14^6$ in expanded form, how many factors will there be?

14614^6 means 14 multiplied by itself 6 times. Therefore, there are 6 factors.

6. What number equals 100 when it is squared?

We are looking for a number xx such that x2=100x^2 = 100. Since 10×10=10010 \times 10 = 100, the number is
1
0.

7. What number equals 8 when it is cubed?

We are looking for a number xx such that x3=8x^3 = 8. Since 2×2×2=82 \times 2 \times 2 = 8, the number is
2.

8. What is the sum of $2^4$ and $7^2$? Write the answer in standard form.

24=2×2×2×2=162^4 = 2 \times 2 \times 2 \times 2 = 16
72=7×7=497^2 = 7 \times 7 = 49
16+49=6516 + 49 = 65

9. Write the following expression in exponential form: $8 \times 8 \times 8 \times 8 \times 3 \times 3$

The expression can be written as 84×328^4 \times 3^2.
1

0. Write the following expression in expanded form: $9^3 \times 7^3$

93=9×9×99^3 = 9 \times 9 \times 9
73=7×7×77^3 = 7 \times 7 \times 7
So, 93×73=(9×9×9)×(7×7×7)9^3 \times 7^3 = (9 \times 9 \times 9) \times (7 \times 7 \times 7).

3. Final Answer

1. $5^6$

2. $7 \times 7 \times 7 \times 7$

3. 32, 27, 121, 64

4. 8, 7, 25, 12

5. 6

6. 10

7. 2

8. 65

9. $8^4 \times 3^2$

1

0. $(9 \times 9 \times 9) \times (7 \times 7 \times 7)$

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