The problem is divided into two exercises. Exercise 1 deals with a linear function $f$ with a coefficient of $\frac{3}{2}$. We need to find the expression of $f(x)$, calculate the image of 6 by $f$, calculate $f(-8)$, $f(-4)$, $f(\frac{4}{3})$, and $f(6\sqrt{5})$, and finally, find the number whose image is 21 by $f$. Exercise 2 deals with a linear function $g$ defined by $g(x) = \frac{7}{2}x$. We need to complete a table of values.
2025/4/25
1. Problem Description
The problem is divided into two exercises.
Exercise 1 deals with a linear function with a coefficient of . We need to find the expression of , calculate the image of 6 by , calculate , , , and , and finally, find the number whose image is 21 by .
Exercise 2 deals with a linear function defined by . We need to complete a table of values.
2. Solution Steps
Exercise 1:
(1) The expression of is given by .
(2) To calculate the image of 6 by , we evaluate :
(3) To calculate , , , and , we substitute these values into the expression of :
(4) To find the number such that , we solve the equation :
Exercise 2:
The function is defined by .
We are given a table with values of 0, -2, 4, and an unknown value. We are also given that is 21 for an unknown and -31.5 for another unknown x.
For , we solve :
For , we solve :
So the complete table is:
x | 0 | -2 | 6 | 4 | -9
---|---|---|---|---|---
g(x) | 0 | -7 | 21 | 14 | -31.5
3. Final Answer
Exercise 1:
(1)
(2)
(3) , , ,
(4)
Exercise 2:
x | 0 | -2 | 6 | 4 | -9
---|---|---|---|---|---
g(x) | 0 | -7 | 21 | 14 | -31.5