The problem is divided into two exercises. Exercise 1 deals with a linear function $f$ with a coefficient of $\frac{3}{2}$. We need to find the expression of $f(x)$, calculate the image of 6 by $f$, calculate $f(-8)$, $f(-4)$, $f(\frac{4}{3})$, and $f(6\sqrt{5})$, and finally, find the number whose image is 21 by $f$. Exercise 2 deals with a linear function $g$ defined by $g(x) = \frac{7}{2}x$. We need to complete a table of values.

AlgebraLinear FunctionsFunction EvaluationSolving Equations
2025/4/25

1. Problem Description

The problem is divided into two exercises.
Exercise 1 deals with a linear function ff with a coefficient of 32\frac{3}{2}. We need to find the expression of f(x)f(x), calculate the image of 6 by ff, calculate f(8)f(-8), f(4)f(-4), f(43)f(\frac{4}{3}), and f(65)f(6\sqrt{5}), and finally, find the number whose image is 21 by ff.
Exercise 2 deals with a linear function gg defined by g(x)=72xg(x) = \frac{7}{2}x. We need to complete a table of values.

2. Solution Steps

Exercise 1:
(1) The expression of f(x)f(x) is given by f(x)=32xf(x) = \frac{3}{2}x.
(2) To calculate the image of 6 by ff, we evaluate f(6)f(6):
f(6)=32(6)=3(3)=9f(6) = \frac{3}{2}(6) = 3(3) = 9
(3) To calculate f(8)f(-8), f(4)f(-4), f(43)f(\frac{4}{3}), and f(65)f(6\sqrt{5}), we substitute these values into the expression of f(x)f(x):
f(8)=32(8)=3(4)=12f(-8) = \frac{3}{2}(-8) = 3(-4) = -12
f(4)=32(4)=3(2)=6f(-4) = \frac{3}{2}(-4) = 3(-2) = -6
f(43)=32(43)=42=2f(\frac{4}{3}) = \frac{3}{2}(\frac{4}{3}) = \frac{4}{2} = 2
f(65)=32(65)=3(35)=95f(6\sqrt{5}) = \frac{3}{2}(6\sqrt{5}) = 3(3\sqrt{5}) = 9\sqrt{5}
(4) To find the number xx such that f(x)=21f(x) = 21, we solve the equation 32x=21\frac{3}{2}x = 21:
x=2123=72=14x = 21 \cdot \frac{2}{3} = 7 \cdot 2 = 14
Exercise 2:
The function is defined by g(x)=72xg(x) = \frac{7}{2}x.
We are given a table with xx values of 0, -2, 4, and an unknown value. We are also given that g(x)g(x) is 21 for an unknown xx and -31.5 for another unknown x.
g(0)=72(0)=0g(0) = \frac{7}{2}(0) = 0
g(2)=72(2)=7g(-2) = \frac{7}{2}(-2) = -7
g(4)=72(4)=7(2)=14g(4) = \frac{7}{2}(4) = 7(2) = 14
For g(x)=21g(x) = 21, we solve 72x=21\frac{7}{2}x = 21:
x=2127=32=6x = 21 \cdot \frac{2}{7} = 3 \cdot 2 = 6
For g(x)=31.5g(x) = -31.5, we solve 72x=31.5\frac{7}{2}x = -31.5:
x=31.527=63227=9x = -31.5 \cdot \frac{2}{7} = -\frac{63}{2} \cdot \frac{2}{7} = -9
So the complete table is:
x | 0 | -2 | 6 | 4 | -9
---|---|---|---|---|---
g(x) | 0 | -7 | 21 | 14 | -31.5

3. Final Answer

Exercise 1:
(1) f(x)=32xf(x) = \frac{3}{2}x
(2) f(6)=9f(6) = 9
(3) f(8)=12f(-8) = -12, f(4)=6f(-4) = -6, f(43)=2f(\frac{4}{3}) = 2, f(65)=95f(6\sqrt{5}) = 9\sqrt{5}
(4) x=14x = 14
Exercise 2:
x | 0 | -2 | 6 | 4 | -9
---|---|---|---|---|---
g(x) | 0 | -7 | 21 | 14 | -31.5

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