The problem asks to find the area of the given figure, which is a combination of rectangles and a triangle. The dimensions are provided in millimeters.

1. Problem Description

The problem asks to find the area of the given figure, which is a combination of rectangles and a triangle. The dimensions are provided in millimeters.

2. Solution Steps

First, we divide the figure into smaller shapes: three rectangles and a triangle.

Rectangle 1 has dimensions 4 mm x 4 mm.

Rectangle 2 has dimensions 2 mm x 5 mm.

Rectangle 3 has dimensions 3 mm x 9 mm.

The triangle has a base of 7 mm and a height of 10 mm.

Calculate the area of each shape:

Area of a rectangle = length * width

Area of a triangle = (1/2) * base * height

Area of Rectangle 1 = $4 \times 4 = 16$ square mm

Area of Rectangle 2 = $2 \times 5 = 10$ square mm

Area of Rectangle 3 = $3 \times 9 = 27$ square mm

Area of Triangle = $(1/2) \times 7 \times 10 = 35$ square mm

Total Area = Area of Rectangle 1 + Area of Rectangle 2 + Area of Rectangle 3 + Area of Triangle

Total Area = $16 + 10 + 27 + 35 = 88$ square mm

3. Final Answer

88 square millimeters