We need to find the area of the given figure, which is an irregular polygon. We can decompose the figure into a rectangle, a smaller rectangle, and a triangle.

1. Problem Description

We need to find the area of the given figure, which is an irregular polygon. We can decompose the figure into a rectangle, a smaller rectangle, and a triangle.

2. Solution Steps

First, let's identify the three shapes in the figure.

Shape 1 is a rectangle with sides 8 yd and 8 yd.

Shape 2 is a rectangle with sides 9 yd and 5 yd.

Shape 3 is a triangle with base 3 yd and height 3 yd.

Area of a rectangle = length * width

Area of a triangle = (1/2) * base * height

Area of Shape 1 = 8 yd * 8 yd = 64 $yd^2$

Area of Shape 2 = 9 yd * 5 yd = 45 $yd^2$

Area of Shape 3 = (1/2) * 3 yd * 3 yd = (1/2) * 9 $yd^2$ = 4.5 $yd^2$

The total area of the figure is the sum of the areas of the three shapes.

Total Area = Area of Shape 1 + Area of Shape 2 + Area of Shape 3

Total Area = 64 $yd^2$ + 45 $yd^2$ + 4.5 $yd^2$ = 113.5 $yd^2$

3. Final Answer

The area of the figure is 113.5 $yd^2$.