We are given three successive discounts: 20%, 50%, and 10%. We want to find the equivalent single discount.

ArithmeticPercentageDiscountsRetail Math
2025/4/26

1. Problem Description

We are given three successive discounts: 20%, 50%, and 10%. We want to find the equivalent single discount.

2. Solution Steps

Let the original price be PP.
After the first discount of 20%, the price becomes P1=P(10.20)=0.8PP_1 = P(1 - 0.20) = 0.8P.
After the second discount of 50%, the price becomes P2=P1(10.50)=0.8P(0.5)=0.4PP_2 = P_1(1 - 0.50) = 0.8P(0.5) = 0.4P.
After the third discount of 10%, the price becomes P3=P2(10.10)=0.4P(0.9)=0.36PP_3 = P_2(1 - 0.10) = 0.4P(0.9) = 0.36P.
The final price is 0.36 times the original price. This means that the total discount is 10.36=0.641 - 0.36 = 0.64.
Therefore, the equivalent single discount is 0.64×100%=64%0.64 \times 100\% = 64\%.

3. Final Answer

The equivalent single discount is 64%.
The answer is D) 64%.

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