The problem is to find the slope $m$ of the line passing through the points $P(1,4)$ and $Q(9,8)$. Then, it appears that the calculation of the slope of the line passing through the point $Q(9,8)$ and $V(2,8)$ is desired. The point $U(-6,1)$ seems to be irrelevant to the presented calculation.

GeometryCoordinate GeometrySlopeLines
2025/4/27

1. Problem Description

The problem is to find the slope mm of the line passing through the points P(1,4)P(1,4) and Q(9,8)Q(9,8). Then, it appears that the calculation of the slope of the line passing through the point Q(9,8)Q(9,8) and V(2,8)V(2,8) is desired. The point U(6,1)U(-6,1) seems to be irrelevant to the presented calculation.

2. Solution Steps

First, we will calculate the slope mPQm_{PQ} of the line passing through points P(1,4)P(1,4) and Q(9,8)Q(9,8) using the slope formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the coordinates of P(1,4)P(1,4) and Q(9,8)Q(9,8), where x1=1x_1 = 1, y1=4y_1 = 4, x2=9x_2 = 9, and y2=8y_2 = 8, we have:
mPQ=8491m_{PQ} = \frac{8 - 4}{9 - 1}
mPQ=48m_{PQ} = \frac{4}{8}
mPQ=12m_{PQ} = \frac{1}{2}
Then we will compute the slope of the line passing through the points Q(9,8)Q(9,8) and V(2,8)V(2,8):
mQV=8829=07=0m_{QV} = \frac{8 - 8}{2 - 9} = \frac{0}{-7} = 0
Note: The image shows m=8191=78m=\frac{8-1}{9-1} = \frac{7}{8}. It used the y-coordinate of Q, but the x-coordinate of P. This is incorrect. It also uses the y coordinate of V and x coordinate of U when they are unrelated to each other.

3. Final Answer

The slope of the line passing through P(1,4)P(1,4) and Q(9,8)Q(9,8) is mPQ=12m_{PQ} = \frac{1}{2}.
The slope of the line passing through Q(9,8)Q(9,8) and V(2,8)V(2,8) is mQV=0m_{QV} = 0.
The value computed in the image is 78\frac{7}{8}, but this is the slope of the line between (1,1) and (9,8).

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