The problem asks us to solve two equations for $k$: a) $\frac{k}{5} + 8 = 9$ b) $\frac{k+8}{5} = 9$

AlgebraLinear EquationsSolving EquationsVariables
2025/4/27

1. Problem Description

The problem asks us to solve two equations for kk:
a) k5+8=9\frac{k}{5} + 8 = 9
b) k+85=9\frac{k+8}{5} = 9

2. Solution Steps

a) k5+8=9\frac{k}{5} + 8 = 9
Subtract 8 from both sides of the equation:
k5+88=98\frac{k}{5} + 8 - 8 = 9 - 8
k5=1\frac{k}{5} = 1
Multiply both sides of the equation by 5:
5k5=515 * \frac{k}{5} = 5 * 1
k=5k = 5
b) k+85=9\frac{k+8}{5} = 9
Multiply both sides of the equation by 5:
5k+85=595 * \frac{k+8}{5} = 5 * 9
k+8=45k + 8 = 45
Subtract 8 from both sides of the equation:
k+88=458k + 8 - 8 = 45 - 8
k=37k = 37

3. Final Answer

a) k=5k = 5
b) k=37k = 37

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