The problem asks us to solve the inequality $2 \le \frac{k}{3}$ and then graph the solution on a number line.

AlgebraInequalitiesSolving InequalitiesNumber LineGraphing Inequalities
2025/4/28

1. Problem Description

The problem asks us to solve the inequality 2k32 \le \frac{k}{3} and then graph the solution on a number line.

2. Solution Steps

First, we need to solve the inequality for kk. To do this, we multiply both sides of the inequality by 3:
2k32 \le \frac{k}{3}
3×23×k33 \times 2 \le 3 \times \frac{k}{3}
6k6 \le k
This can be written as:
k6k \ge 6
This means that kk is greater than or equal to

6. To graph this on the number line, we need a closed circle (or a filled-in circle) at 6, since $k$ can be equal to

6. We then draw an arrow to the right, indicating that $k$ can be any value greater than

6.

3. Final Answer

The solution to the inequality is k6k \ge 6.
On the number line, we should plot a closed circle at 6 and an arrow extending to the right.