We need to solve four unit conversion problems: a. Convert 2 meters to centimeters. b. Estimate how many liters a 1-gallon jug can hold. c. Convert a metric ton (1000 kg) to pounds. d. Convert a temperature increase of 10 degrees Celsius to Fahrenheit.

ArithmeticUnit ConversionMeasurementMetric SystemImperial UnitsTemperature Conversion
2025/4/28

1. Problem Description

We need to solve four unit conversion problems:
a. Convert 2 meters to centimeters.
b. Estimate how many liters a 1-gallon jug can hold.
c. Convert a metric ton (1000 kg) to pounds.
d. Convert a temperature increase of 10 degrees Celsius to Fahrenheit.

2. Solution Steps

a. Conversion of meters to centimeters.
We know that 1 meter = 100 centimeters.
Therefore, 2 meters = 2 * 100 centimeters.
b. Conversion of gallons to liters.
We know that 1 gallon is approximately equal to 3.785 liters.
c. Conversion of metric tons to pounds.
We know that 1 metric ton = 1000 kilograms and 1 kilogram is approximately equal to 2.20462 pounds.
Therefore, 1 metric ton = 1000 * 2.20462 pounds.
d. Conversion of Celsius temperature increase to Fahrenheit.
The formula to convert a temperature change from Celsius to Fahrenheit is:
ΔTF=95ΔTC\Delta T_F = \frac{9}{5} \Delta T_C
Where ΔTF\Delta T_F is the change in Fahrenheit and ΔTC\Delta T_C is the change in Celsius.
Given that ΔTC=10\Delta T_C = 10 degrees Celsius, we can find ΔTF\Delta T_F.
a. Calculation:
2 meters = 2 * 100 centimeters = 200 centimeters.
b. Estimation:
1 gallon \approx 3.785 liters.
c. Calculation:
1 metric ton = 1000 kg
1 kg \approx 2.20462 lbs
1 metric ton \approx 1000 * 2.20462 lbs = 2204.62 lbs
Therefore, 1 metric ton \approx 2205 lbs.
d. Calculation:
ΔTF=95ΔTC\Delta T_F = \frac{9}{5} \Delta T_C
ΔTF=9510\Delta T_F = \frac{9}{5} * 10
ΔTF=18\Delta T_F = 18 degrees Fahrenheit.

3. Final Answer

a. 200 centimeters
b. Approximately 3.785 liters
c. Approximately 2205 pounds
d. 18 degrees Fahrenheit

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