The problem asks to compare the following numbers: a. $10.30$ and $10.3$ b. $5.06$ and $5.60$ c. $1.1$ and $1.099$ Also, we need to round $3.14159$ to the nearest ten-thousandth.

1. Problem Description

The problem asks to compare the following numbers:

a. $10.30$ and $10.3$

b. $5.06$ and $5.60$

c. $1.1$ and $1.099$

Also, we need to round $3.14159$ to the nearest ten-thousandth.

2. Solution Steps

a. Comparing $10.30$ and $10.3$.

We can rewrite $10.3$ as $10.30$.

Since $10.30 = 10.30$, the two numbers are equal.

b. Comparing $5.06$ and $5.60$.

We compare the tenths place. $0 < 6$, so $5.06 < 5.60$.

c. Comparing $1.1$ and $1.099$.

We can rewrite $1.1$ as $1.100$.

Comparing $1.100$ and $1.099$, the ones place is the same. Comparing the tenths place, $1 > 0$, so $1.100 > 1.099$.

Thus, $1.1 > 1.099$.

d. Rounding $3.14159$ to the nearest ten-thousandth.

The ten-thousandth place is the fourth digit after the decimal point.

The number is $3.14159$.

The digit in the ten-thousandth place is $5$.

The digit to the right of $5$ is $9$.

Since $9 \ge 5$, we round up the $5$ to $6$.

Thus, $3.14159$ rounded to the nearest ten-thousandth is $3.1416$.

3. Final Answer

a. $10.30 = 10.3$

b. $5.06 < 5.60$

c. $1.1 > 1.099$

d. $3.1416$