Alana and Harrison played a game 60 times. Alana won 45% of the games and Harrison won 20% of the games. We need to find out how many games they drew.

1. Problem Description

Alana and Harrison played a game 60 times. Alana won 45% of the games and Harrison won 20% of the games. We need to find out how many games they drew.

2. Solution Steps

First, we calculate the number of games Alana won. This is 45% of

6

0. $Alana\_wins = 0.45 \times 60$

Next, we calculate the number of games Harrison won. This is 20% of

6

0. $Harrison\_wins = 0.20 \times 60$

Then, we add the number of games Alana won and the number of games Harrison won to find the total number of games won.

$Total\_wins = Alana\_wins + Harrison\_wins$

Finally, we subtract the total number of games won from the total number of games played to find the number of games that were drawn.

$Draws = Total\_games - Total\_wins$

Where $Total\_games = 60$

$Alana\_wins = 0.45 \times 60 = 27$

$Harrison\_wins = 0.20 \times 60 = 12$

$Total\_wins = 27 + 12 = 39$

$Draws = 60 - 39 = 21$

3. Final Answer

They drew 21 games.