The problem asks us to evaluate the expression $(-8)^2 \div (-2)^3 \times (-4)^2$.

ArithmeticOrder of OperationsExponentsInteger Arithmetic
2025/5/4

1. Problem Description

The problem asks us to evaluate the expression (8)2÷(2)3×(4)2(-8)^2 \div (-2)^3 \times (-4)^2.

2. Solution Steps

First, we calculate each exponential term.
(8)2=(8)×(8)=64(-8)^2 = (-8) \times (-8) = 64
(2)3=(2)×(2)×(2)=8(-2)^3 = (-2) \times (-2) \times (-2) = -8
(4)2=(4)×(4)=16(-4)^2 = (-4) \times (-4) = 16
Now, we substitute these values into the expression:
64÷(8)×1664 \div (-8) \times 16
Next, we perform the division:
64÷(8)=864 \div (-8) = -8
Finally, we perform the multiplication:
8×16=128-8 \times 16 = -128

3. Final Answer

-128

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