The problem asks us to determine the output sequence of the variable $num$ when the provided pseudocode is executed. The pseudocode involves a loop that continues until the variable $x$ is greater than or equal to the variable $num$. Inside the loop, $x$ is incremented by 5, $num$ is decremented by $x$, and $num$ is printed.

1. Problem Description

The problem asks us to determine the output sequence of the variable $num$ when the provided pseudocode is executed. The pseudocode involves a loop that continues until the variable $x$ is greater than or equal to the variable $num$. Inside the loop, $x$ is incremented by 5, $num$ is decremented by $x$, and $num$ is printed.

2. Solution Steps

We need to trace the values of $x$ and $num$ during each iteration of the loop.

Initialization:

$x = 10$

$num = 50$

Loop 1:

Condition: $x (10) >= num (50)$ is false.

$x = x + 5 = 10 + 5 = 15$

$num = num - x = 50 - 15 = 35$

Print $num$: 35

Loop 2:

Condition: $x (15) >= num (35)$ is false.

$x = x + 5 = 15 + 5 = 20$

$num = num - x = 35 - 20 = 15$

Print $num$: 15

Loop 3:

Condition: $x (20) >= num (15)$ is false.

$x = x + 5 = 20 + 5 = 25$

$num = num - x = 15 - 25 = -10$

Print $num$: -10

Loop 4:

Condition: $x (25) >= num (-10)$ is true.

The loop terminates.

Therefore, the output sequence of $num$ is $35, 15, -10$. However, this is not one of the options. The closest options are (3) 35,

1

5. I am missing the end condition to correctly calculate the sequence of $num$ values. Going back and re-examining the pseudo-code reveals an "Until x >= num" statement which implies that the loop ends once $x$ becomes greater than or equal to $num$. The important operations are $x = x + 5$ and $num = num - x$.

Round 1:

$x = 10, num = 50$

$x >= num$ is false.

$x = 10 + 5 = 15$

$num = 50 - 15 = 35$

Print $num = 35$

Round 2:

$x = 15, num = 35$

$x >= num$ is false.

$x = 15 + 5 = 20$

$num = 35 - 20 = 15$

Print $num = 15$

Round 3:

$x = 20, num = 15$

$x >= num$ is true, exit loop.

3. Final Answer

(3) 35, 15