We need to calculate the value of the expression $\sin(\frac{\pi}{6}) + \cos(\frac{\pi}{3})$.

1. Problem Description

We need to calculate the value of the expression $\sin(\frac{\pi}{6}) + \cos(\frac{\pi}{3})$.

2. Solution Steps

First, we need to find the value of $\sin(\frac{\pi}{6})$. Recall that $\frac{\pi}{6}$ radians is equal to $30^{\circ}$. We know that $\sin(30^{\circ}) = \frac{1}{2}$. Therefore, $\sin(\frac{\pi}{6}) = \frac{1}{2}$.

Next, we need to find the value of $\cos(\frac{\pi}{3})$. Recall that $\frac{\pi}{3}$ radians is equal to $60^{\circ}$. We know that $\cos(60^{\circ}) = \frac{1}{2}$. Therefore, $\cos(\frac{\pi}{3}) = \frac{1}{2}$.

Now, we can substitute these values into the expression:

$\sin(\frac{\pi}{6}) + \cos(\frac{\pi}{3}) = \frac{1}{2} + \frac{1}{2}$.

Adding these values together:

$\frac{1}{2} + \frac{1}{2} = \frac{2}{2} = 1$.

3. Final Answer

1