The first problem asks us to express the fraction $\frac{3\sqrt{2} - \sqrt{3}}{2\sqrt{3} - \sqrt{2}}$ in the form $\frac{\sqrt{m}}{\sqrt{n}}$, where $m$ and $n$ are whole numbers. The second problem asks us to solve the equation $\sqrt{x+8} + \sqrt{x+1} = 7$.

AlgebraRadicalsSimplificationEquationsRationalizationSquare Roots
2025/3/19

1. Problem Description

The first problem asks us to express the fraction 323232\frac{3\sqrt{2} - \sqrt{3}}{2\sqrt{3} - \sqrt{2}} in the form mn\frac{\sqrt{m}}{\sqrt{n}}, where mm and nn are whole numbers.
The second problem asks us to solve the equation x+8+x+1=7\sqrt{x+8} + \sqrt{x+1} = 7.

2. Solution Steps

Problem 1:
First, we rationalize the denominator of the given fraction:
323232=32323223+223+2\frac{3\sqrt{2} - \sqrt{3}}{2\sqrt{3} - \sqrt{2}} = \frac{3\sqrt{2} - \sqrt{3}}{2\sqrt{3} - \sqrt{2}} \cdot \frac{2\sqrt{3} + \sqrt{2}}{2\sqrt{3} + \sqrt{2}}
Now, we multiply the numerators and denominators:
Numerator: (323)(23+2)=32(23)+32(2)3(23)3(2)=66+666=56(3\sqrt{2} - \sqrt{3})(2\sqrt{3} + \sqrt{2}) = 3\sqrt{2}(2\sqrt{3}) + 3\sqrt{2}(\sqrt{2}) - \sqrt{3}(2\sqrt{3}) - \sqrt{3}(\sqrt{2}) = 6\sqrt{6} + 6 - 6 - \sqrt{6} = 5\sqrt{6}
Denominator: (232)(23+2)=(23)2(2)2=4(3)2=122=10(2\sqrt{3} - \sqrt{2})(2\sqrt{3} + \sqrt{2}) = (2\sqrt{3})^2 - (\sqrt{2})^2 = 4(3) - 2 = 12 - 2 = 10
So, the expression becomes 5610=62=64=62.542.5=1510\frac{5\sqrt{6}}{10} = \frac{\sqrt{6}}{2} = \frac{\sqrt{6}}{\sqrt{4}} = \frac{\sqrt{6 \cdot 2.5}}{\sqrt{4 \cdot 2.5}} = \frac{\sqrt{15}}{\sqrt{10}}.
However, we have 5610=256100=150100\frac{5\sqrt{6}}{10} = \frac{\sqrt{25} \sqrt{6}}{\sqrt{100}} = \frac{\sqrt{150}}{\sqrt{100}}
Problem 2:
We are given x+8+x+1=7\sqrt{x+8} + \sqrt{x+1} = 7.
Isolate one of the square roots: x+8=7x+1\sqrt{x+8} = 7 - \sqrt{x+1}
Square both sides: (x+8)2=(7x+1)2(\sqrt{x+8})^2 = (7 - \sqrt{x+1})^2
x+8=4914x+1+(x+1)x+8 = 49 - 14\sqrt{x+1} + (x+1)
x+8=50+x14x+1x+8 = 50+x - 14\sqrt{x+1}
Subtract xx from both sides: 8=5014x+18 = 50 - 14\sqrt{x+1}
42=14x+1-42 = -14\sqrt{x+1}
3=x+13 = \sqrt{x+1}
Square both sides: 9=x+19 = x+1
x=8x = 8
Check the solution: 8+8+8+1=16+9=4+3=7\sqrt{8+8} + \sqrt{8+1} = \sqrt{16} + \sqrt{9} = 4 + 3 = 7. Thus, x=8x=8 is a solution.

3. Final Answer

For the first problem, the answer is 150100\frac{\sqrt{150}}{\sqrt{100}}.
For the second problem, the answer is 8.

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