Find the measure of angle 1, denoted as $m\angle 1$. We are given that the arc $AC$ has a measure of $71^\circ$ and the arc $DB$ has a measure of $82^\circ$.

GeometryCircle GeometryAngles in a CircleIntersecting ChordsArc Measure
2025/5/9

1. Problem Description

Find the measure of angle 1, denoted as m1m\angle 1. We are given that the arc ACAC has a measure of 7171^\circ and the arc DBDB has a measure of 8282^\circ.

2. Solution Steps

The measure of an angle formed by two chords intersecting inside a circle is equal to one-half the sum of the intercepted arcs.
In this case, 1\angle 1 is formed by the intersection of chords ADAD and BCBC. The intercepted arcs are ACAC and DBDB.
Therefore, the measure of 1\angle 1 is given by
m1=12(marc AC+marc DB)m\angle 1 = \frac{1}{2}(m\text{arc }AC + m\text{arc }DB)
m1=12(71+82)m\angle 1 = \frac{1}{2}(71^\circ + 82^\circ)
m1=12(153)m\angle 1 = \frac{1}{2}(153^\circ)
m1=76.5m\angle 1 = 76.5^\circ

3. Final Answer

7

6. 5°

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