The distance-time graph shows the cheetah's journey. The problem asks for the cheetah's velocity between 5 seconds and 15 seconds.

Applied MathematicsVelocityDistance-Time GraphPhysicsRate of Change
2025/5/12

1. Problem Description

The distance-time graph shows the cheetah's journey. The problem asks for the cheetah's velocity between 5 seconds and 15 seconds.

2. Solution Steps

The velocity is calculated as the change in distance divided by the change in time.
velocity=change in distancechange in time \text{velocity} = \frac{\text{change in distance}}{\text{change in time}}
From the graph:
At t1=5t_1 = 5 seconds, the distance d1d_1 is approximately 125 meters.
At t2=15t_2 = 15 seconds, the distance d2d_2 is approximately 200 meters.
The change in distance is d2d1=200125=75d_2 - d_1 = 200 - 125 = 75 meters.
The change in time is t2t1=155=10t_2 - t_1 = 15 - 5 = 10 seconds.
velocity=7510=7.5 m/s \text{velocity} = \frac{75}{10} = 7.5 \text{ m/s}

3. Final Answer

The velocity of the cheetah between 5 and 15 seconds is 7.5 m/s.

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