The problem asks us to find the velocity of a cheetah between 5 and 15 seconds, given a distance-time graph of its movement. We need to extract the distance traveled at 5 seconds and 15 seconds from the graph and then calculate the velocity using the formula velocity = distance / time.

Applied MathematicsPhysicsKinematicsVelocityGraph Interpretation
2025/5/12

1. Problem Description

The problem asks us to find the velocity of a cheetah between 5 and 15 seconds, given a distance-time graph of its movement. We need to extract the distance traveled at 5 seconds and 15 seconds from the graph and then calculate the velocity using the formula velocity = distance / time.

2. Solution Steps

First, we need to find the distance traveled at 5 seconds and 15 seconds from the graph.
At 5 seconds, the distance traveled is approximately 125 meters.
At 15 seconds, the distance traveled is approximately 225 meters.
Now, we can calculate the change in distance and change in time.
Change in distance, Δd=d15d5=225125=100\Delta d = d_{15} - d_5 = 225 - 125 = 100 meters.
Change in time, Δt=t15t5=155=10\Delta t = t_{15} - t_5 = 15 - 5 = 10 seconds.
Now, we use the formula for velocity:
v=ΔdΔtv = \frac{\Delta d}{\Delta t}
v=10010=10v = \frac{100}{10} = 10 m/s.

3. Final Answer

10.0 m/s

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