The problem asks to calculate the average speed of a sparrow between 4 and 14 seconds, given a distance-time graph.

1. Problem Description

The problem asks to calculate the average speed of a sparrow between 4 and 14 seconds, given a distance-time graph.

2. Solution Steps

To find the average speed, we need to calculate the total distance traveled and the total time elapsed during the specified interval. The average speed is given by the formula:

$Average \ Speed = \frac{Total \ Distance \ Traveled}{Total \ Time \ Elapsed}$

From the graph:

At time $t_1 = 4$ seconds, the distance traveled is $d_1 = 2$ meters.

At time $t_2 = 14$ seconds, the distance traveled is $d_2 = 35$ meters.

The total distance traveled between 4 and 14 seconds is:

$Total \ Distance = d_2 - d_1 = 35 - 2 = 33$ meters.

The total time elapsed is:

$Total \ Time = t_2 - t_1 = 14 - 4 = 10$ seconds.

Therefore, the average speed is:

$Average \ Speed = \frac{33 \ meters}{10 \ seconds} = 3.3 \ m/s$

3. Final Answer

The average speed of the sparrow between 4 and 14 seconds is 3.3 m/s.