The problem asks us to find the smallest of three consecutive integers that sum to 60.

1. Problem Description

The problem asks us to find the smallest of three consecutive integers that sum to

6

0.

2. Solution Steps

Let $n$ be the smallest of the three consecutive integers.

Then the three consecutive integers are $n$, $n+1$, and $n+2$.

Their sum is $n + (n+1) + (n+2) = 60$.

Combining like terms, we get $3n + 3 = 60$.

Subtracting 3 from both sides gives $3n = 57$.

Dividing both sides by 3 gives $n = 19$.

The three integers are 19, 20, and

2

1. Their sum is $19 + 20 + 21 = 60$.

The smallest of the three integers is

1

9.

3. Final Answer

19