The problem states: "The sum of 4 consecutive even integers is 68. What is the least of the 4 integers?"

1. Problem Description

The problem states: "The sum of 4 consecutive even integers is

6

8. What is the least of the 4 integers?"

2. Solution Steps

Let $x$ be the smallest of the four consecutive even integers. Then the other three are $x+2$, $x+4$, and $x+6$.

The sum of the four consecutive even integers is given as

6

8. So, we can write the equation:

$x + (x+2) + (x+4) + (x+6) = 68$

Combine like terms:

$4x + 12 = 68$

Subtract 12 from both sides of the equation:

$4x = 68 - 12$

$4x = 56$

Divide both sides by 4:

$x = \frac{56}{4}$

$x = 14$

The four consecutive even integers are 14, 16, 18, and

2

0. $14+16+18+20=68$

The smallest of the four integers is

1

4.

3. Final Answer

14