The problem states that there are 3 consecutive odd integers that sum to 57. We need to find the greatest of these three integers. The analysis result section solves a slightly different problem with the sum equal to 87.

AlgebraLinear EquationsInteger PropertiesConsecutive Integers
2025/5/12

1. Problem Description

The problem states that there are 3 consecutive odd integers that sum to
5

7. We need to find the greatest of these three integers. The analysis result section solves a slightly different problem with the sum equal to

8
7.

2. Solution Steps

Let the three consecutive odd integers be xx, x+2x+2, and x+4x+4, where xx is an odd integer.
The sum of these three integers is given as
5

7. Therefore, we can write the equation:

x+(x+2)+(x+4)=57x + (x+2) + (x+4) = 57
Combine like terms:
3x+6=573x + 6 = 57
Subtract 6 from both sides of the equation:
3x=5763x = 57 - 6
3x=513x = 51
Divide both sides by 3:
x=513x = \frac{51}{3}
x=17x = 17
The three consecutive odd integers are 17, 19, and
2

1. The greatest of these integers is

2
1.

3. Final Answer

21

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