The problem states that the sum of 3 consecutive even integers is 60. We are asked to find the value of the least integer.

1. Problem Description

The problem states that the sum of 3 consecutive even integers is

6

0. We are asked to find the value of the least integer.

2. Solution Steps

Let $x$ be the smallest even integer. Then the next two consecutive even integers are $x+2$ and $x+4$. The sum of these three integers is 60, so we have the equation:

$x + (x+2) + (x+4) = 60$.

Combine like terms:

$3x + 6 = 60$.

Subtract 6 from both sides:

$3x = 60 - 6$

$3x = 54$.

Divide both sides by 3:

$x = \frac{54}{3}$

$x = 18$.

The smallest even integer is

1

8. The next two consecutive even integers are $18+2=20$ and $18+4=22$. We can check that $18+20+22 = 60$.

3. Final Answer

18