The problem asks to find four consecutive integers whose sum is -30.

1. Problem Description

The problem asks to find four consecutive integers whose sum is -

3

0.

2. Solution Steps

Let the four consecutive integers be $n, n+1, n+2,$ and $n+3$.

Their sum is given as -

3

0. Therefore, we can write the equation:

$n + (n+1) + (n+2) + (n+3) = -30$

Combine the terms on the left side:

$4n + 6 = -30$

Subtract 6 from both sides:

$4n = -30 - 6$

$4n = -36$

Divide both sides by 4:

$n = \frac{-36}{4}$

$n = -9$

The four consecutive integers are:

$n = -9$

$n+1 = -9 + 1 = -8$

$n+2 = -9 + 2 = -7$

$n+3 = -9 + 3 = -6$

3. Final Answer

The four integers are -9, -8, -7, -6.