The problem states that five consecutive even integers have a sum of -50. We need to find the least of these integers.

1. Problem Description

The problem states that five consecutive even integers have a sum of -

5

0. We need to find the least of these integers.

2. Solution Steps

Let the five consecutive even integers be $n, n+2, n+4, n+6, n+8$.

The sum of these integers is given as -

5

0. So, we have the equation:

$n + (n+2) + (n+4) + (n+6) + (n+8) = -50$

Combining the terms, we get:

$5n + 20 = -50$

Subtract 20 from both sides of the equation:

$5n = -50 - 20$

$5n = -70$

Divide both sides by 5:

$n = \frac{-70}{5}$

$n = -14$

The five consecutive even integers are -14, -12, -10, -8, -

6. The least of these integers is -

1

4.

3. Final Answer

-14