We are given that five consecutive integers add up to $-5$. We are asked to find the greatest of these five integers.

AlgebraLinear EquationsConsecutive IntegersProblem Solving
2025/5/12

1. Problem Description

We are given that five consecutive integers add up to 5-5. We are asked to find the greatest of these five integers.

2. Solution Steps

Let the five consecutive integers be x,x+1,x+2,x+3,x, x+1, x+2, x+3, and x+4x+4. Their sum is given as 5-5.
So, we can write the equation:
x+(x+1)+(x+2)+(x+3)+(x+4)=5x + (x+1) + (x+2) + (x+3) + (x+4) = -5
Combining the terms, we get:
5x+10=55x + 10 = -5
Subtracting 10 from both sides, we have:
5x=5105x = -5 - 10
5x=155x = -15
Dividing both sides by 5, we get:
x=3x = -3
So, the five consecutive integers are:
x=3x = -3
x+1=3+1=2x+1 = -3 + 1 = -2
x+2=3+2=1x+2 = -3 + 2 = -1
x+3=3+3=0x+3 = -3 + 3 = 0
x+4=3+4=1x+4 = -3 + 4 = 1
The integers are 3,2,1,0,1-3, -2, -1, 0, 1. The greatest of these integers is 11.

3. Final Answer

1

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