The problem is to evaluate the expression $ -((-2)^2) \div (-3)^3 $.

ArithmeticOrder of OperationsExponentsFractionsInteger Arithmetic
2025/5/12

1. Problem Description

The problem is to evaluate the expression ((2)2)÷(3)3 -((-2)^2) \div (-3)^3 .

2. Solution Steps

First, we evaluate (2)2(-2)^2:
(2)2=(2)×(2)=4(-2)^2 = (-2) \times (-2) = 4
So the expression becomes:
(4)÷(3)3 - (4) \div (-3)^3
which is 4÷(3)3 -4 \div (-3)^3
Next, we evaluate (3)3(-3)^3:
(3)3=(3)×(3)×(3)=9×(3)=27(-3)^3 = (-3) \times (-3) \times (-3) = 9 \times (-3) = -27
The expression now becomes:
4÷(27)-4 \div (-27)
A division by a number is the same as multiplying by its reciprocal.
So we have:
4÷(27)=4×(127)=427=427-4 \div (-27) = -4 \times (\frac{1}{-27}) = \frac{-4}{-27} = \frac{4}{27}

3. Final Answer

The final answer is 427\frac{4}{27}.

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