The problem asks us to graph the exponential function $y = 0.5 \cdot 2^x$. We can achieve this by selecting several $x$ values, calculating corresponding $y$ values, and plotting these points on the provided coordinate plane.

AlgebraExponential FunctionsGraphingFunction Evaluation
2025/5/13

1. Problem Description

The problem asks us to graph the exponential function y=0.52xy = 0.5 \cdot 2^x. We can achieve this by selecting several xx values, calculating corresponding yy values, and plotting these points on the provided coordinate plane.

2. Solution Steps

First, let's create a table of values for the function y=0.52xy = 0.5 \cdot 2^x.
We will select some integer values for xx between -3 and
3.
For x=3x = -3:
y=0.523=0.518=1218=116=0.0625y = 0.5 \cdot 2^{-3} = 0.5 \cdot \frac{1}{8} = \frac{1}{2} \cdot \frac{1}{8} = \frac{1}{16} = 0.0625
For x=2x = -2:
y=0.522=0.514=1214=18=0.125y = 0.5 \cdot 2^{-2} = 0.5 \cdot \frac{1}{4} = \frac{1}{2} \cdot \frac{1}{4} = \frac{1}{8} = 0.125
For x=1x = -1:
y=0.521=0.512=1212=14=0.25y = 0.5 \cdot 2^{-1} = 0.5 \cdot \frac{1}{2} = \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4} = 0.25
For x=0x = 0:
y=0.520=0.51=0.5y = 0.5 \cdot 2^0 = 0.5 \cdot 1 = 0.5
For x=1x = 1:
y=0.521=0.52=1y = 0.5 \cdot 2^1 = 0.5 \cdot 2 = 1
For x=2x = 2:
y=0.522=0.54=2y = 0.5 \cdot 2^2 = 0.5 \cdot 4 = 2
For x=3x = 3:
y=0.523=0.58=4y = 0.5 \cdot 2^3 = 0.5 \cdot 8 = 4
Here is a table summarizing the values:
x | y
---|---
-3 | 0.0625
-2 | 0.125
-1 | 0.25
0 | 0.5
1 | 1
2 | 2
3 | 4
Now, we can plot these points on the coordinate plane and connect them to sketch the graph of the function.

3. Final Answer

The graph of y=0.52xy = 0.5 \cdot 2^x is an exponential curve passing through the points (-3, 0.0625), (-2, 0.125), (-1, 0.25), (0, 0.5), (1, 1), (2, 2), and (3, 4).
(Note: I cannot physically plot the graph, but the description above tells you how to plot it.)

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