We are given the profit function $P(q) = 1200 - 10q - q^2$, where $q$ is the quantity of units produced and sold. We want to find the number of units that must be produced and sold to break even, meaning the profit is zero, $P(q) = 0$. Thus we need to solve the equation $1200 - 10q - q^2 = 0$ for $q$.

AlgebraQuadratic EquationsProfit FunctionFactoringProblem SolvingOptimization
2025/3/22

1. Problem Description

We are given the profit function P(q)=120010qq2P(q) = 1200 - 10q - q^2, where qq is the quantity of units produced and sold. We want to find the number of units that must be produced and sold to break even, meaning the profit is zero, P(q)=0P(q) = 0. Thus we need to solve the equation 120010qq2=01200 - 10q - q^2 = 0 for qq.

2. Solution Steps

We need to solve the quadratic equation
120010qq2=01200 - 10q - q^2 = 0
Rearranging the terms, we have:
q2+10q1200=0q^2 + 10q - 1200 = 0
We can factor the quadratic expression:
(q30)(q+40)=0(q - 30)(q + 40) = 0
So, q30=0q - 30 = 0 or q+40=0q + 40 = 0.
This gives us two possible values for qq:
q=30q = 30 or q=40q = -40.
Since qq represents the number of units produced and sold, it must be a non-negative number. Therefore, q=40q = -40 is not a valid solution. Thus, q=30q = 30.

3. Final Answer

The number of units that must be produced and sold to break even is
3

0. Answer: (b)

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