The initial weight of a fruit bag is $\frac{7}{10}$ kg. Emily adds more fruits, and the new weight is $\frac{19}{20}$ kg. We need to find the weight of the fruits added by Emily.

1. Problem Description

The initial weight of a fruit bag is $\frac{7}{10}$ kg. Emily adds more fruits, and the new weight is $\frac{19}{20}$ kg. We need to find the weight of the fruits added by Emily.

2. Solution Steps

To find the weight of the fruits added, we need to subtract the initial weight from the final weight.

So, we need to calculate $\frac{19}{20} - \frac{7}{10}$.

First, we need to find a common denominator for the two fractions. The least common multiple of 20 and 10 is

2

0. We rewrite $\frac{7}{10}$ as an equivalent fraction with a denominator of 20:

$\frac{7}{10} = \frac{7 \times 2}{10 \times 2} = \frac{14}{20}$.

Now we can subtract the fractions:

$\frac{19}{20} - \frac{14}{20} = \frac{19-14}{20} = \frac{5}{20}$.

Simplify the fraction by dividing both numerator and denominator by their greatest common divisor, which is 5:

$\frac{5}{20} = \frac{5 \div 5}{20 \div 5} = \frac{1}{4}$.

3. Final Answer

$\frac{1}{4}$