The problem asks us to find which of the following fractions: $\frac{4}{15}$, $\frac{7}{15}$, $\frac{9}{15}$, and $\frac{13}{15}$ is closest to 1.

1. Problem Description

The problem asks us to find which of the following fractions: $\frac{4}{15}$, $\frac{7}{15}$, $\frac{9}{15}$, and $\frac{13}{15}$ is closest to

1.

2. Solution Steps

To determine which fraction is closest to 1, we can find the difference between each fraction and

1.

* For $\frac{4}{15}$, the difference is $1 - \frac{4}{15} = \frac{15}{15} - \frac{4}{15} = \frac{11}{15}$.

* For $\frac{7}{15}$, the difference is $1 - \frac{7}{15} = \frac{15}{15} - \frac{7}{15} = \frac{8}{15}$.

* For $\frac{9}{15}$, the difference is $1 - \frac{9}{15} = \frac{15}{15} - \frac{9}{15} = \frac{6}{15}$.

* For $\frac{13}{15}$, the difference is $1 - \frac{13}{15} = \frac{15}{15} - \frac{13}{15} = \frac{2}{15}$.

The smallest difference indicates the fraction closest to

1. Comparing the differences $\frac{11}{15}$, $\frac{8}{15}$, $\frac{6}{15}$, and $\frac{2}{15}$, we see that $\frac{2}{15}$ is the smallest. Therefore, $\frac{13}{15}$ is the closest to

1.

3. Final Answer

$\frac{13}{15}$