The problem asks to evaluate the expression $(+\frac{1}{2}) - (+\frac{2}{3}) - (-1\frac{1}{6})$.

1. Problem Description

The problem asks to evaluate the expression $(+\frac{1}{2}) - (+\frac{2}{3}) - (-1\frac{1}{6})$.

2. Solution Steps

First, rewrite the mixed number $-1\frac{1}{6}$ as an improper fraction:

$$-1\frac{1}{6} = -\frac{1 \times 6 + 1}{6} = -\frac{7}{6}$$

Next, remove the parentheses and signs:

$$+\frac{1}{2} - (+\frac{2}{3}) - (-\frac{7}{6}) = \frac{1}{2} - \frac{2}{3} + \frac{7}{6}$$

Find the least common denominator (LCD) of 2, 3, and

6. The LCD is

6. Rewrite the fractions with the LCD:

$$\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6}$$

$$\frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6}$$

$$\frac{7}{6} = \frac{7}{6}$$

Now, substitute these equivalent fractions into the expression:

$$\frac{3}{6} - \frac{4}{6} + \frac{7}{6}$$

Combine the fractions:

$$\frac{3 - 4 + 7}{6} = \frac{-1 + 7}{6} = \frac{6}{6}$$

Finally, simplify the fraction:

$$\frac{6}{6} = 1$$

3. Final Answer

1