We need to use the numbers 1, 3, and 5 to fill in the blanks such that the resulting percentage is equal to a fraction with a denominator of 20. That is, we need to find $xy$ and $z$ such that $xy \% = \frac{z}{20}$.

ArithmeticPercentagesFractionsNumber PropertiesEquation Solving
2025/3/24

1. Problem Description

We need to use the numbers 1, 3, and 5 to fill in the blanks such that the resulting percentage is equal to a fraction with a denominator of
2

0. That is, we need to find $xy$ and $z$ such that $xy \% = \frac{z}{20}$.

2. Solution Steps

First, we need to remember that percentage means "out of 100". Therefore, xy%=xy100xy \% = \frac{xy}{100}. So, we are looking for a two-digit number xyxy and a single-digit number zz such that xy100=z20\frac{xy}{100} = \frac{z}{20}.
Multiplying both sides by 100, we get
xy=100z20=5zxy = \frac{100z}{20} = 5z.
Since we have the numbers 1, 3, and 5, we can make the following two-digit numbers: 13, 15, 31, 35, 51,
5

3. And $z$ must be one of the three numbers.

If z=1z=1, xy=5z=5xy=5z=5. This is not a two-digit number, so z1z \neq 1.
If z=3z=3, xy=5z=15xy=5z=15.
If z=5z=5, xy=5z=25xy=5z=25. We don't have a 2, so z5z \neq 5.
Therefore, xy=15xy=15 and z=3z=3.
The equation becomes 15%=32015\% = \frac{3}{20}. Let us verify this.
15%=1510015\% = \frac{15}{100}. If we divide both numerator and denominator by 5, we get 15100=15÷5100÷5=320\frac{15}{100} = \frac{15 \div 5}{100 \div 5} = \frac{3}{20}.

3. Final Answer

15%=32015 \% = \frac{3}{20}

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