The problem asks to find the area of the given shape. The shape is a rectangle with a smaller rectangle cut out. The outer rectangle has dimensions 111 inches by 42 inches. The cut-out rectangle has a width of 66 inches and the height is 42 - 18 = 24 inches.

1. Problem Description

The problem asks to find the area of the given shape. The shape is a rectangle with a smaller rectangle cut out. The outer rectangle has dimensions 111 inches by 42 inches. The cut-out rectangle has a width of 66 inches and the height is 42 - 18 = 24 inches.

2. Solution Steps

First, calculate the area of the outer rectangle.

$Area_{outer} = length * width$

$Area_{outer} = 111 * 42 = 4662$ square inches.

Next, calculate the area of the cut-out rectangle.

$Area_{cutout} = length * width$

$Area_{cutout} = 66 * (42-18) = 66 * 24 = 1584$ square inches.

Finally, subtract the area of the cut-out rectangle from the area of the outer rectangle to find the area of the shape.

$Area_{shape} = Area_{outer} - Area_{cutout}$

$Area_{shape} = 4662 - 1584 = 3078$ square inches.

3. Final Answer

The area of the shape is 3078 square inches.