The problem states that Queen Elizabeth II gave 64 pence each to 64 men and 64 women on Maundy Thursday in 1990. We need to calculate the total amount of money given away in pence and express the answer in the form $2^a$, where $a$ is an integer.

ArithmeticExponentsPowers of 2MultiplicationWord Problem
2025/3/25

1. Problem Description

The problem states that Queen Elizabeth II gave 64 pence each to 64 men and 64 women on Maundy Thursday in
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9
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0. We need to calculate the total amount of money given away in pence and express the answer in the form $2^a$, where $a$ is an integer.

2. Solution Steps

First, calculate the total number of recipients. Since she gave money to 64 men and 64 women, the total number of recipients is:
64+64=12864 + 64 = 128
Each person received 64 pence. Therefore, the total amount of money given away is:
128×64128 \times 64
Now, we need to express 128 and 64 as powers of 2:
128=27128 = 2^7
64=2664 = 2^6
Substitute these into the expression for the total amount of money:
27×262^7 \times 2^6
Using the rule for multiplying exponents with the same base, am×an=am+na^m \times a^n = a^{m+n}, we have:
27+6=2132^{7+6} = 2^{13}

3. Final Answer

The total amount of money given away is 2132^{13} pence.

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