The image contains three division problems. We need to solve for: a) $160 \div 2$ b) $168 \div 3$ c) $246 \div 2$ d) $200 \div 4$

ArithmeticDivisionInteger Arithmetic
2025/5/27

1. Problem Description

The image contains three division problems. We need to solve for:
a) 160÷2160 \div 2
b) 168÷3168 \div 3
c) 246÷2246 \div 2
d) 200÷4200 \div 4

2. Solution Steps

a) 160÷2160 \div 2:
We can divide 160 by 2 using long division or by recognizing that 160 is 16 times
1

0. $160 \div 2 = (16 \times 10) \div 2 = (16 \div 2) \times 10 = 8 \times 10 = 80$

b) 168÷3168 \div 3:
We can divide 168 by 3 using long division.
168÷3=56168 \div 3 = 56
3×50=1503 \times 50 = 150
168150=18168-150 = 18
3×6=183 \times 6 = 18
50+6=5650+6=56
c) 246÷2246 \div 2:
We can divide 246 by 2 using long division or by breaking it into smaller parts.
246÷2=(200+40+6)÷2=(200÷2)+(40÷2)+(6÷2)=100+20+3=123246 \div 2 = (200 + 40 + 6) \div 2 = (200 \div 2) + (40 \div 2) + (6 \div 2) = 100 + 20 + 3 = 123
d) 200÷4200 \div 4:
We can divide 200 by 4 using long division or recognition.
200÷4=(2×100)÷4=2×(100÷4)=2×25=50200 \div 4 = (2 \times 100) \div 4 = 2 \times (100 \div 4) = 2 \times 25 = 50

3. Final Answer

a) 160÷2=80160 \div 2 = 80
b) 168÷3=56168 \div 3 = 56
c) 246÷2=123246 \div 2 = 123
d) 200÷4=50200 \div 4 = 50

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