The problem is to evaluate the expression $-3^2 - (-2)^3$.

ArithmeticOrder of OperationsExponentsInteger Arithmetic
2025/6/1

1. Problem Description

The problem is to evaluate the expression 32(2)3-3^2 - (-2)^3.

2. Solution Steps

First, we need to evaluate 32-3^2. Note that this is (32)-(3^2) and not (3)2(-3)^2.
32=3×3=93^2 = 3 \times 3 = 9
So, 32=9-3^2 = -9.
Next, we need to evaluate (2)3(-2)^3.
(2)3=(2)×(2)×(2)=4×(2)=8(-2)^3 = (-2) \times (-2) \times (-2) = 4 \times (-2) = -8.
Therefore, we have:
32(2)3=9(8)=9+8=1-3^2 - (-2)^3 = -9 - (-8) = -9 + 8 = -1.

3. Final Answer

-1

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