Masane went to a shop with $1425.00. He bought a shirt, a pair of shoes, and an electric iron. The cost of the electric iron is $85.00 less than the cost of the shirt and the cost of the shoes. The cost of the shoes is four times the cost of the shirt. After paying for the items, he was left with $88.00. Calculate the cost of the electric iron.

AlgebraLinear EquationsWord ProblemSystem of Equations
2025/6/3

1. Problem Description

Masane went to a shop with $1425.
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0. He bought a shirt, a pair of shoes, and an electric iron. The cost of the electric iron is $85.00 less than the cost of the shirt and the cost of the shoes. The cost of the shoes is four times the cost of the shirt. After paying for the items, he was left with $88.

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0. Calculate the cost of the electric iron.

2. Solution Steps

Let ss be the cost of the shirt, hh be the cost of the shoes, and ii be the cost of the electric iron. We are given the following information:
\begin{enumerate}
\item i=s+h85i = s + h - 85
\item h=4sh = 4s
\item s+h+i+88=1425s + h + i + 88 = 1425
\end{enumerate}
We can substitute the second equation into the first equation to get:
i=s+4s85=5s85i = s + 4s - 85 = 5s - 85
Now, we can substitute h=4sh = 4s and i=5s85i = 5s - 85 into the third equation:
s+4s+(5s85)+88=1425s + 4s + (5s - 85) + 88 = 1425
10s85+88=142510s - 85 + 88 = 1425
10s+3=142510s + 3 = 1425
10s=142210s = 1422
s=142.2s = 142.2
Now we can find the cost of the shoes:
h=4s=4(142.2)=568.8h = 4s = 4(142.2) = 568.8
And the cost of the electric iron:
i=5s85=5(142.2)85=71185=626i = 5s - 85 = 5(142.2) - 85 = 711 - 85 = 626
Therefore, the cost of the electric iron is $
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3. Final Answer

The cost of the electric iron is $626.
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