The given Venn diagram shows the number of elements that are multiples of 2 and multiples of 3. The problem asks two questions: 1. How many elements are divisible by both 2 and 3?

Discrete MathematicsVenn DiagramsSet TheoryDivisibilityCounting
2025/6/4

1. Problem Description

The given Venn diagram shows the number of elements that are multiples of 2 and multiples of

3. The problem asks two questions:

1. How many elements are divisible by both 2 and 3?

2. What is the total number of elements?

2. Solution Steps

Question 1:
The elements divisible by both 2 and 3 are those that are in the intersection of the "Multiples of 2" and "Multiples of 3" sets. From the Venn diagram, the intersection contains the number

2. Therefore, there are 2 elements divisible by both 2 and

3.
Question 2:
To find the total number of elements, we need to add up the number of elements in each region of the Venn diagram.
The region "Multiples of 2 only" contains 3 elements.
The intersection region contains 2 elements.
The region "Multiples of 3 only" contains 2 elements.
The region outside the circles contains 3 elements.
So, the total number of elements is 3+2+2+3=103 + 2 + 2 + 3 = 10.

3. Final Answer

Q.6.2.1: 2
Q.6.2.2: 10

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