A straight line passes through the points $(3, -2)$ and $(4, 5)$ and intersects the y-axis at $-23$. We are asked to find the equation of the line.

GeometryLinear EquationsSlopeY-interceptCoordinate Geometry
2025/6/10

1. Problem Description

A straight line passes through the points (3,2)(3, -2) and (4,5)(4, 5) and intersects the y-axis at 23-23. We are asked to find the equation of the line.

2. Solution Steps

We are given two points (3,2)(3, -2) and (4,5)(4, 5). We can find the slope mm of the line using the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the given points, (x1,y1)=(3,2)(x_1, y_1) = (3, -2) and (x2,y2)=(4,5)(x_2, y_2) = (4, 5), we have:
m=5(2)43=71=7m = \frac{5 - (-2)}{4 - 3} = \frac{7}{1} = 7
Since the line intersects the y-axis at 23-23, this means the y-intercept bb is 23-23. The equation of a line in slope-intercept form is given by:
y=mx+by = mx + b
Substituting the values of mm and bb, we get:
y=7x23y = 7x - 23

3. Final Answer

The equation of the line is y=7x23y = 7x - 23.

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