A boat is moving eastward at 1.6 m/s parallel to a bank. Person A is standing on the bank and observes people B and C on the boat. (1) B is moving in the same direction as the boat at 2.1 m/s relative to the boat. What is the velocity of B as seen by A? (2) C is moving in the opposite direction as the boat at 2.7 m/s relative to the boat. What is the velocity of C as seen by A? (3) In 3.0 seconds, in which direction and by how many meters does C move relative to the bank?

Applied MathematicsKinematicsRelative MotionVelocityPhysics
2025/6/22

1. Problem Description

A boat is moving eastward at 1.6 m/s parallel to a bank. Person A is standing on the bank and observes people B and C on the boat.
(1) B is moving in the same direction as the boat at 2.1 m/s relative to the boat. What is the velocity of B as seen by A?
(2) C is moving in the opposite direction as the boat at 2.7 m/s relative to the boat. What is the velocity of C as seen by A?
(3) In 3.0 seconds, in which direction and by how many meters does C move relative to the bank?

2. Solution Steps

(1) Since B is moving in the same direction as the boat, the velocities add up.
vBA=vboat,A+vB,boatv_{BA} = v_{boat, A} + v_{B, boat}
vBA=1.6 m/s+2.1 m/s=3.7 m/sv_{BA} = 1.6 \text{ m/s} + 2.1 \text{ m/s} = 3.7 \text{ m/s} eastward.
(2) Since C is moving in the opposite direction as the boat, the velocities subtract.
vCA=vboat,AvC,boatv_{CA} = v_{boat, A} - v_{C, boat}
vCA=1.6 m/s2.7 m/s=1.1 m/sv_{CA} = 1.6 \text{ m/s} - 2.7 \text{ m/s} = -1.1 \text{ m/s}
The negative sign indicates westward direction. Therefore, C is moving westward at 1.1 m/s as seen by A.
(3) We already know the velocity of C relative to A, which is the bank. It is moving westward at 1.1 m/s.
The distance covered in 3.0 seconds is given by:
d=v×td = v \times t
d=1.1 m/s×3.0 s=3.3 md = 1.1 \text{ m/s} \times 3.0 \text{ s} = 3.3 \text{ m}
Therefore, C moves 3.3 m westward.

3. Final Answer

(1) Eastward at 3.7 m/s.
(2) Westward at 1.1 m/s.
(3) Westward 3.3 m.

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