The problem asks us to calculate the values of four expressions: a) $\sqrt{81}$ b) $\sqrt{3^2}$ c) $\sqrt{(\frac{2}{3})^2}$ d) $\sqrt{7} \times \sqrt{3}$

ArithmeticSquare RootsExponentsRadicalsSimplification
2025/3/30

1. Problem Description

The problem asks us to calculate the values of four expressions:
a) 81\sqrt{81}
b) 32\sqrt{3^2}
c) (23)2\sqrt{(\frac{2}{3})^2}
d) 7×3\sqrt{7} \times \sqrt{3}

2. Solution Steps

a) We need to find the square root of
8

1. Since $9 \times 9 = 81$, we have $\sqrt{81} = 9$.

b) We need to find the square root of 323^2.
32=3×3=93^2 = 3 \times 3 = 9, so 32=9\sqrt{3^2} = \sqrt{9}.
Since 3×3=93 \times 3 = 9, we have 9=3\sqrt{9} = 3.
Alternatively, a2=a\sqrt{a^2} = |a|. So, 32=3=3\sqrt{3^2} = |3| = 3.
c) We need to find the square root of (23)2(\frac{2}{3})^2.
(23)2=23×23=49(\frac{2}{3})^2 = \frac{2}{3} \times \frac{2}{3} = \frac{4}{9}, so (23)2=49\sqrt{(\frac{2}{3})^2} = \sqrt{\frac{4}{9}}.
Since 23×23=49\frac{2}{3} \times \frac{2}{3} = \frac{4}{9}, we have 49=23\sqrt{\frac{4}{9}} = \frac{2}{3}.
Alternatively, a2=a\sqrt{a^2} = |a|. So, (23)2=23=23\sqrt{(\frac{2}{3})^2} = |\frac{2}{3}| = \frac{2}{3}.
d) We need to find the product of 7\sqrt{7} and 3\sqrt{3}.
a×b=a×b\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}
So, 7×3=7×3=21\sqrt{7} \times \sqrt{3} = \sqrt{7 \times 3} = \sqrt{21}.

3. Final Answer

a) 9
b) 3
c) 23\frac{2}{3}
d) 21\sqrt{21}

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