The problem asks us to find the square root of 2025. That is, we need to find a number $x$ such that $x^2 = 2025$.

ArithmeticSquare RootPrime FactorizationNumber Properties
2025/3/30

1. Problem Description

The problem asks us to find the square root of
2
0
2

5. That is, we need to find a number $x$ such that $x^2 = 2025$.

2. Solution Steps

We can find the square root of 2025 by prime factorization.
2025=5×405=5×5×81=5×5×9×9=52×922025 = 5 \times 405 = 5 \times 5 \times 81 = 5 \times 5 \times 9 \times 9 = 5^2 \times 9^2.
Thus, 2025=52×92=52×92=5×9=45\sqrt{2025} = \sqrt{5^2 \times 9^2} = \sqrt{5^2} \times \sqrt{9^2} = 5 \times 9 = 45.
Alternatively, we can notice that 402=160040^2 = 1600 and 502=250050^2 = 2500, so the answer should be between 40 and
5

0. Since the last digit of 2025 is 5, the last digit of the square root should be

5. Therefore, we can try $45^2 = 45 \times 45 = (40+5)(40+5) = 40^2 + 2(40 \times 5) + 5^2 = 1600 + 400 + 25 = 2025$.

Thus 2025=45\sqrt{2025} = 45.

3. Final Answer

45

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