The problem asks to simplify the given fractions to their lowest terms. The fractions are: a) $ -\frac{18}{30} $ b) $ \frac{16}{48} $ c) $ -\frac{7}{21} $ d) $ -\frac{162}{24} $

1. Problem Description

The problem asks to simplify the given fractions to their lowest terms. The fractions are:

a) $-\frac{18}{30}$

b) $\frac{16}{48}$

c) $-\frac{7}{21}$

d) $-\frac{162}{24}$

2. Solution Steps

a) $-\frac{18}{30}$

The greatest common divisor (GCD) of 18 and 30 is

6. Divide both numerator and denominator by 6:

$-\frac{18 \div 6}{30 \div 6} = -\frac{3}{5}$

b) $\frac{16}{48}$

The greatest common divisor (GCD) of 16 and 48 is

1

6. Divide both numerator and denominator by 16:

$\frac{16 \div 16}{48 \div 16} = \frac{1}{3}$

c) $-\frac{7}{21}$

The greatest common divisor (GCD) of 7 and 21 is

7. Divide both numerator and denominator by 7:

$-\frac{7 \div 7}{21 \div 7} = -\frac{1}{3}$

d) $-\frac{162}{24}$

The greatest common divisor (GCD) of 162 and 24 is

6. Divide both numerator and denominator by 6:

$-\frac{162 \div 6}{24 \div 6} = -\frac{27}{4}$

3. Final Answer

a) $-\frac{3}{5}$

b) $\frac{1}{3}$

c) $-\frac{1}{3}$

d) $-\frac{27}{4}$