The problem is to determine the output of the given Pascal program. The program initializes a variable $a$ to 0, then iterates through a loop where $b$ goes from 1 to 7. Inside the loop, $a$ is updated by adding $b$ to it, and the new value of $a$ is printed.

Discrete MathematicsAlgorithmsIterationSeriesSummation
2025/3/31

1. Problem Description

The problem is to determine the output of the given Pascal program. The program initializes a variable aa to 0, then iterates through a loop where bb goes from 1 to

7. Inside the loop, $a$ is updated by adding $b$ to it, and the new value of $a$ is printed.

2. Solution Steps

Let's trace the execution of the program:
- Initialize a=0a = 0.
- Loop from b=1b = 1 to 77:
- b=1b = 1: a=a+b=0+1=1a = a + b = 0 + 1 = 1. Print a=1a = 1.
- b=2b = 2: a=a+b=1+2=3a = a + b = 1 + 2 = 3. Print a=3a = 3.
- b=3b = 3: a=a+b=3+3=6a = a + b = 3 + 3 = 6. Print a=6a = 6.
- b=4b = 4: a=a+b=6+4=10a = a + b = 6 + 4 = 10. Print a=10a = 10.
- b=5b = 5: a=a+b=10+5=15a = a + b = 10 + 5 = 15. Print a=15a = 15.
- b=6b = 6: a=a+b=15+6=21a = a + b = 15 + 6 = 21. Print a=21a = 21.
- b=7b = 7: a=a+b=21+7=28a = a + b = 21 + 7 = 28. Print a=28a = 28.

3. Final Answer

The output of the program is:
1
3
6
10
15
21
28

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